Some of the most common questions asked by engineering aspirants is related to JEE Main marks and ranks. However, from 2019, the results of the exam will be calculated through the process of normalization which would include percentiles as well. Thus, with the exam just around the corner, such queries would be on the rise. Before delving deeper, let me first tell you what does terms like – Percentage, Percentile and Normalisation mean.
For the uninitiated, Percentage and Percentile are two totally different entities. While Percentage is a number out of 100, Percentile reflects how many candidates have scored below that candidate in an exam. A Percentile score is the value below which a certain percent of observations fall.
On the other hand, Normalisation is the process of ensuring that students neither benefit nor receive any disadvantage by the difficulty of their Boards.
Now, given below is an indicative table that gives you an idea about JEE Main Marks vs Ranks i.e. what rank you could expect to obtain on securing a certain score in JEE Mai. Please note that the data given below is completely indicative in nature.
|JEE Main Scores||JEE Main Ranks (CRL)|
|249 – 200||1392-5565|
|139-86||23484 – 40815|
|85-0||83215 – 950000|
After JEE Main Paper 1 being completely held online from 2019 and in multiple sessions, another common query that would bother engineering candidates is – ‘How is JEE Main Rank Calculated?”.
From this year, the exam will be held across different days and sessions, thus, there is a possibility of some candidates getting an easy paper while others getting a tough question paper to answer. Thus, to ensure equality, NTA will adopt the process of normalization to determine JEE Main 2019 results and ranks. Candidates appearing for the exam will be ranked on the basis of their percentile scores which will based on a pre-determined formula.
Formula to calculate JEE Main 2019 scores
100 X Number of candidates appeared in the ‘Session’ with raw score Equal TO OR LESS than the candidate
Total number of aspirants who have appeared in the ‘Session’
Listed below are the steps of Normalization and Preparation of JEE Main 2019 rank list:
Step 1: Distribution of candidates in two days and in two shifts per day
The first step will be distributing aspirants into four sessions randomly so that each session has approximately equal number of students. The four sessions would be:
· Session-1: Day-1 Shift-1
· Session-2: Day-1 Shift-2
· Session-3: Day-2 Shift-1
· Session-4: Day-2 Shift-2
Step 2: Preparation of Results for each Session
JEE Main 2019 results for each of the session will be prepared in the form of:
1. Raw Scores
2. Separate percentiles scores for each of the three subjects -Mathematics, Physics, Chemistry – and the Total.
For each candidate, 4 percentile score will be calculated which includes:
Step 3: Compilation of NTA score and Preparation of Overall Merit/Rank List
Now, the percentile scores for the Total Raw Score for all the four sessions (in the image above) will be merged. This will be known as NTA scores.
Now, these NTA scores will be used to compile JEE Main result and further JEE Main 2019 Merit List / Ranking.
NTA will be conducting JEE Main 2019 twice – first time in January and second time in April. Candidates should note that the rank list of JEE Main will be declared after both January and April exams have concluded.